Click on the images to open a new tab and see them in full resolution.
1.4 Version 1 Answers
1.4 Version 2 Answers
1.4 Version 3 Answers
12. Use the Squeeze Thoerem to show that lim x approaches 0 (x^2 cos 24 pi x) = Illustrate by graphing the functions f(x) = -x^2, g(x) = x^2 cos 24 pi x, and h(x) = x^2 on the same screen. Let f(x) = -x^2, g(x) = x^2 cos 24 pi x, and h(x) = x^2. Then -1 <= cos 24 pi x <= 1. f(x) <= x^2 cos 24 pi x <= h(x). Since lim x approaches 0 of f(x) = lim of x approaches 0 of h(x) = 0 by the squeeze Theorem we have lim x approaches 0 of g(x) = 0.
